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Revisions 4


9 months ago
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This is a test. Anyone should understand why the nonlinear system $\dot{x} = -x^5$ is asymptotically stable around the equilibrium point $x = 0$ even though its linearized tangent system $\dot{x} = 0$ at $x=0$ is Lyapunov-stable but not asymptotically stable. $$ E =\gamma m c^2$$
This is a test. Anyone should understand why the nonlinear system $\dot{x} = -x^5$ is asymptotically stable around the equilibrium point $x = 0$ even though its linearized tangent system $\dot{x} = 0$ at $x=0$ is Lyapunov-stable but not asymptotically stable. $$ E =\gamma c^2$$
#latex
#latex
9 months ago
LaTeX Support
LaTeX Support
This is a test. Anyone should understand why the nonlinear system $\dot{x} = -x^5$ is asymptotically stable around the equilibrium point $x = 0$ even though its linearized tangent system $\dot{x} = 0$ at $x=0$ is Lyapunov-stable but not asymptotically stable. $$ E =\gamma c^2$$
Does anyone understand why the nonlinear system $\dot{x} = -x^5$ is asymptotically stable around the equilibrium point $x = 0$ even though its linearized tangent system $\dot{x} = 0$ at $x=0$ is Lyapunov-stable but not asymptotically stable?
#latex
#latex
9 months ago
LaTeX Support
LaTeX Support
Does anyone understand why the nonlinear system $\dot{x} = -x^5$ is asymptotically stable around the equilibrium point $x = 0$ even though its linearized tangent system $\dot{x} = 0$ at $x=0$ is Lyapunov-stable but not asymptotically stable?
Does anyone understand why the nonlinear system $$\dot{x} = -x^5$$ is asymptotically stable around the equilibrium point $$x = 0$$ even though its linearized tangent system $$\dot{x} = 0$$ at $$x=0$$ is Lyapunov-stable but not asymptotically stable?
#latex
#latex
9 months ago
Original
LaTeX Support

Does anyone understand why the nonlinear system $$\dot{x} = -x^5$$ is asymptotically stable around the equilibrium point $$x = 0$$ even though its linearized tangent system $$\dot{x} = 0$$ at $$x=0$$ is Lyapunov-stable but not asymptotically stable?
#latex