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This is a test. Anyone should understand why the nonlinear system $\dot{x} = -x^5$ is asymptotically stable around the equilibrium point $x = 0$ even though its linearized tangent system $\dot{x} = 0$ at $x=0$ is Lyapunov-stable but not asymptotically stable.
$$ E =\gamma m c^2$$

Posted one year ago
Edited one year ago
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Answers 2

Trying paste of an image again like this image: file

Posted one year ago

Using the button file, I would like to preview $E = \gamma m c^2$ where $\gamma = \frac{1}{\sqrt{1-\beta^2}}$ and $\beta = \frac{v}{c}$.

But there is a problem with the superscript (upper limit) in sum functions...
$\sum_{n=1}^{\infty} 2^{-n} = 1$

Posted one year ago
Edited 6 months ago

Your answer

2 Answers
one year ago
4 months ago